Mit Hilfe des Ansatzes E = Epot + Ekin = − e2 / ( 4 π ε0 r ) + ( m / 2 ) v2 erhält man daraus :
Energie des Wasserstoffatoms im Zustand mit der Hauptquantenzahl n:
E
www.walter-fendt.deUsing the formulation E = Epot + Ekin = − e2 / ( 4 π ε0 r ) + ( m / 2 ) v2, we get :
Energy of the hydrogen atom for the state of principal quantum number n:
E
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